6x^2+28x+48=16

Solution for 6x^2+28x+48=16 equation:

6x^2+28x+48=16

We move all terms to the left:

6x^2+28x+48-(16)=0

We add all the numbers together, and all the variables

6x^2+28x+32=0

a = 6; b = 28; c = +32;
Δ = b2-4ac
Δ = 282-4·6·32
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4}{2*6}=\frac{-32}{12}
=-2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4}{2*6}=\frac{-24}{12}
=-2
$